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(C) $1$. The circuit consists of an internal resistance of $1 \ \Omega$ in series with the battery.$2$. There is a $2 \ \Omega$ resistor in series wit

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$8$

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(C) $1$. The circuit consists of an internal resistance of $1 \ \Omega$ in series with the battery.$2$. There is a $2 \ \Omega$ resistor in series with the combination of two $2 \ \Omega$ resistors connected in parallel.$3$. The equivalent resistance of the two $2 \ \Omega$ resistors in parallel is $R_p = \frac{2 	imes 2}{2 + 2} = 1 \ \Omega$.$4$. The total resistance of the upper branch is $R_{upper} = 1 \ \Omega 	ext{ (internal)} + 2 \ \Omega + 1 \ \Omega = 4 \ \Omega$.$5$. The voltmeter is assumed to have infinite resistance, so it does not affect the circuit. The $4 \ \Omega$ resistor is in series with the rest of the circuit.$6$. The total equivalent resistance of the circuit is $R_{eq} = 4 \ \Omega + 4 \ \Omega = 8 \ \Omega$.

What is the equivalent resistance of the circuit in $\Omega$?

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